Question

plzz answer this sum as Soon as possible.....​

Answer 1

Step-by-step explanation:

it is given that ,

triangle ABC ~triangle DEF,

we know that the ratios of areas of two similar triangles is equal to the ratio of the sequence of any two corresponding sides .

are(triangleABC)/ar(triangleDEF) =BC square/EF square.

64/121=BC square/EF square.

(8/11) square=(BC/15.4)square.

8/11=BC/15.4.

BC=15.4×8/11.

BC=11.2 cm

Answer 2

Answer:

8.14cm

Step-by-step explanation:

∆ABC ≈ ∆DEF

therefore

area ∆ABC ÷ BC = area ∆DEF ÷ EF

=> (64)/(BC) = (121)/15.4

=> BC = 64 × 15.4 ÷ 121

=> BC = 8.14cm