Question

Plzz answer thisss...

Answer 1

Radius r of sphere = 6 over 2 = 3 cm

Volume of sphere = 4 over 3r3

If R is the radius and H is the height of the cylinder, then

Volume of water in the cylindrical beaker = R2H

Volume of rise in level of water = R2 (40)

If 'N' is the number of spheres dropped in the beaker then volume of spheres = Volume of water rose in the beaker

N 4 over 3r3 = R2(40)

N 4 over 3(3)3 = 9 9 40

N = 90

Answer 2

Answer:is 90

Step-by-step explanation:

volume of cylinder = n(volume of solid sphere)

πr²h = n(4/3πr³)

22/7×9×9×40 = n(4/3×22/7×3×3×3)

solve this u get answer n= 90

∴no of solid spheres is 90

************hope it helps u*******************