Question

Plzz answer
What will be the reading of ammeter??​

Answer 1

Answer:

2 amp

Explanation:

1. Calculate the Total resistance

$in \: parallel \: r = \frac{4 \times 5}{ 4 + 5} \\ \\ r = \frac{20}{9} ohms$

2. Calculate Total Current

$v = ir \\ \\ = > i = \frac{v}{r} \\ \\ i = \frac{10}{ \frac{20}{9} } \\ \\ i = \frac{9}{2} = 4.5 \: ampere$

3. Calculate the current relation

LET the current in 4ohms be x and the other be y

x is the reading of ammeter as it is in series with it

Since 4 and 5 are parallelly connected voltage across each is same

$v_1 = v_2 \\ \\ = > x \times 4 = y \times 5 \\ \\ wkt \\ total \: current \: i = x + y \\ = > x + y = 4.5 \\ \\ = > 4x = 5y \\ \\ = > 4x = 5(4.5 - y) \\ \\ 4x = 22.5 - 5y \\ \\ = > 9y = 22.5 \\ \\ = > y = 2.5 \\ \\ = > x = 4.5 - 2.5 \\ = > x = 2amp$

HOPE IT HELPS

Answer 2

Answer:

Current = 10/5

I = 2A

So, reading of ammeter = 2 ampere