Math, asked by zainab2269, 6 months ago

Plzz answerrr thissssssssss

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Answered by neerajshami3
1

Answer:

 y =   \sqrt[3]{p + r}  \\  {y}^{2}  = p + r \\ r =  {y}^{2} - p

(11) \\ y = 2 \sqrt{x - 8}  \\ y - 2 =  \sqrt{x - 8}  \\  \sqrt{y - 2}  = x - 8 \\ x =   \sqrt{y - 2 }  + 8

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