Question

Plzz any one answer Q 8

Answer 1

p= 2000 ruppee
r= 6%
t= 1 year

I = p×t×r =2000×1×6%
=120 ruppee
amount at the end of 1st year
=P+I= rs200+rs120= rs2120

amount withdrawn= rs 700
balance the end of 1st year = rs2120-rs700=1420

now P = rs1420
t =3 year
r = 6%
I = P×T×R ÷ 100 = 1420×3×6÷100
= 1420×18÷10 = 2556=255.60

balance after 3years=P+I
= rs1420+ rs255.60
= rs 1675.60