Question

plzz anyone say the answer and the actual question is to find the area of quadrilateral from the Ch mensuration of class8​

Answer 1

Mark it as brainliest....

Answer 2

Answer:

Ar. of Parallelogram=1/2×h×(sum of ||'s)

=$\frac{1}{2} \times 2 \times (8 + 12)$

=20 sq. cm

Area of ∆=1/2×b×h

=

=$\frac{1}{2} \times 12 \times 4$

=24 sq. cm

Area of Pentagon=24+20

=44sq. cm