Question

plzz anyone solve this...​

Answer 1

Answer:

a^x+x^a+a^a

Is the ans correct?

Answer 2

Answer:

LET THE ANSWER BE EQUAL TO K

TAKE LOGS ON BOTH SIDES

WE GET

X LOG A LOG E + A LOG X LOG E + A LOG A LOG E= LOG K

TAKE LOG E COMMON AND SHIFT TO THE OTHER SIDE

X LOG A + A LOG X + A LOG A= LOG K -LOG E

LOG (A^X + X^A + A^A ) = LOG (K/E)

TAKE ANTILOGS

A^X + X^A + A^A = K/E

THEREFORE K = E*(A^X + X^A + A^A)