Question

plzz attach a pic of ur solution ​

Answer 1

$HEYA \: \\ \\ 3 {}^{(4 log_{9}(x + 1) )} = 2 {}^{(2 log_{2}(x)) } + 3 \\ \\ 3 {}^{(4 log_{3 {}^{2} }(x + 1)) } = 2 {}^{( log_{2}(x) {}^{2} ) } + 3 \\ \\ 3 {}^{( log_{3}(x + 1) {}^{2}) } = 2 {}^{( log_{2}(x) {}^{2} ) } + 3 \\ \\ (x + 1) {}^{2} = x { }^{2} + 3 \\ becoz \: \: a {}^{ log_{a}(m) } = m \\ \\ x {}^{2} + 1 + 2x = x {}^{2} + 3 \\ \\ 2x = 2 \\ \\ x = 1$