Question

plzz can anyone solve this.....​

Answer 1

Answer:

option 2

Explanation:

solution : charge enclosed inside the cylinderical surface is ,  = linear charge density of wire × length of cylinder

= Q coulomb/cm × 100cm = 100Q Coulombs

now, from Gauss theorem,

electric flux through cylindrical surface = charge enclosed/permittivity of medium

=100Q/EO(option 2)

Answer 2

$\large \sf{\green{Here \: Is \: Your \: Answer:-}}$

‍$\huge \red{ \mathtt{Option \: 2}}$