Question

plzz can someone solve this sum it very difficult ​

Answer 1

$\sf \large \bigg \{ \bigg( \frac{1}{3} \bigg)^{3} \bigg\} \times {\bigg( \frac{3}{2} \bigg)}^{2} \div \bigg \{ \bigg( \frac{2}{3} \bigg)^{ - 1} \bigg\}^{ 3} \\ \\ \to\sf \bigg( \frac{1}{3} \bigg)^{3} \times {\bigg( \frac{3}{2} \bigg)}^{2} \div {\bigg( \frac{2}{3} \bigg)}^{( - 1) \times 3} \\ \\ \to \sf \frac{1}{ {3}^{3} } \times \frac{ {3}^{2} }{2 {}^{2} } \div {\bigg( \frac{2}{3} \bigg)}^{ - 3} \\ \\ \to \sf\bigg (\frac{1}{27} \times \frac{9}{4} \bigg) \div {\bigg( \frac{3}{2} \bigg)}^{3} \\ \\ \to \sf\bigg( \frac{9}{27 \times 4} \bigg) \div \frac{ {3}^{3} }{ {2}^{3} } \\ \\ \sf \to\bigg( \frac{ \cancel9}{ \cancel9 \times 3 \times 4} \bigg) \times \frac{ {2}^{3} }{ {3}^{3} } \\ \\ \to \sf \frac{1}{12} \times \frac{8}{27} \\ \\ \to \sf\frac{1}{3 \times \cancel4} \times \frac{\cancel4 \times 2}{27} \: \: = \red{ \frac{2}{81} }$