Physics, asked by satyendra312, 1 year ago

plzz describe it me fast

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Answered by Anonymous

0

Hey mate!

Refer the attachment!

:)

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Answered by rejaurrahman00633

0

cosA=0•6=6/10=b/H

b=6k

h=10k

by Pythagoras p=8k

so; 5 sinA-3tanA

5×p/h-3×p/b

5×8k/10k-3×8k/6k

4-4

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