plzz do que.(i) to que.(v)
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1) 8
2) activation energy of the reaction
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I. (a) 8
II. 2.5 molal aqueous solution means 2.5 moles of solute in 1 kg solvent(water)
so, moles of solute=2.5
moles of water=1000/18=55.55(approx)
so mole fraction = 2.5/(2.5+55.55)=0.043
(b) 0.043
III. (a) ∆T=Kb.m
IV. (a) nature of electrolyte
V. (c) Activation energy of reaction
I hope you are satisfied with this answer .
Plz make the answer as brainlist answer.
I. (a) 8
II. 2.5 molal aqueous solution means 2.5 moles of solute in 1 kg solvent(water)
so, moles of solute=2.5
moles of water=1000/18=55.55(approx)
so mole fraction = 2.5/(2.5+55.55)=0.043
(b) 0.043
III. (a) ∆T=Kb.m
IV. (a) nature of electrolyte
V. (c) Activation energy of reaction
I hope you are satisfied with this answer .
Plz make the answer as brainlist answer.
Ankush001:
bro plz make brainlist answer
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