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HELLO DEAR FRIEND
GIVEN,
a² + b² = 34
ab = 12
then,
1.> 3(a + b)² + 5(a - b)²
3(a² + b² + 2ab) + 5(a² + b² -2ab)
3(34 + 2(12) ) + 5(34 - 2(12) )
3(34 + 24) + 5(34 - 24)
3(58) + 5(10)
174 + 50
= 224
2> 7(a - b)² - 2(a + b)²
7(a² + b² - 2ab) - 2(a² + b² + 2ab)
7(34 - 2(12) ) - 2(34 + 2(12) )
7(34 - 24) - 2(34 + 24)
7(10) - 2(58)
70 - 116
= - 186
HOPE IT HELPS
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