plzz do question no 11
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Hope it will help you out of the problem
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Ananya1993:
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kr diye hmm
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Heya !!
cosA/(1-sinA) + cosA/(1+sinA) = 4
=> cosA(1+sinA) + cosA(1-sinA) / (1–sin²A) = 4
=> cosA + sinAcosA + cosA – sinAcosA / (1–sin²A) = 4
=> 2cosA / cos²A = 4 [ sin²A + cos²A = 1]
=> 2 / cosA = 4
=> 2secA = 4
=> secA = 4/2
=> secA = 2
Thus, A = 60°.
Hope my ans.'s satisfactory.☺
cosA/(1-sinA) + cosA/(1+sinA) = 4
=> cosA(1+sinA) + cosA(1-sinA) / (1–sin²A) = 4
=> cosA + sinAcosA + cosA – sinAcosA / (1–sin²A) = 4
=> 2cosA / cos²A = 4 [ sin²A + cos²A = 1]
=> 2 / cosA = 4
=> 2secA = 4
=> secA = 4/2
=> secA = 2
Thus, A = 60°.
Hope my ans.'s satisfactory.☺
thanks
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