Math, asked by archanadss2811, 8 months ago

plzz do this question plzz help me I am poor in maths plzz solve it ​

Attachments:

Answers

Answered by spiderman2019
0

Answer:

Step-by-step explanation:

Let A complete the work in x days and B in y days.

So in one day,  A does 1/x work and B does 1/y work.  

Given, A and B together do the work in 15 days.

So in one day they together do 1/15 of work .

=> 1/x + 1/y = 1/15 --- (i)

Given , A's one day work = 3/2 times B's one day work.

=> 1/x =  3/2 * 1/y.

=> 1/x - 3/2y = 0 ---- (ii)

Subtract (ii) from (i)

1/x + 1/y = 1/15

1/x - 3/2y = 0

-   +            -

--------------------

3/2y + 1/y = 1/15

=> 5/2y = 1/15

=> 2y = 75

=> y = 75/2 = 37.5 days.

substitute value of y in (i),

=> 1/x + 1/y = 1/15

=> 1/x + 2/75 = 1/15

=>1/x = 1/15 - 2/75  = 3/75

=> x = 25 days.

Thus A can do the work in 25 days and B can do work in 37.5 days.

Similar questions