Question

Plzz explain briefly....question no.22

Answer 1

Take our specially designed Maths revision test to check your Conceptual Understanding Start Here
close
Next Gurukul Sign Up
menu
X
Sign in or Register for a free account

Download the Free App
Next Gurukul
K-12 Wiki
News
Knowledge World
Exam Corner
Q & A Forum
Experts Panel
Ask
+
Academic Questions and Answers Forum, 94000+ Questions asked
View all questions
Syeda answered 1 year(s) ago
Express hcf of 468 ,222 as 468x+222y where x,y are integers in two different ways?
Express hcf of 468, 222 as 468x + 222y where x, y are integers in two different ways?


person
Asked by Anithasoundar

May 16

6 Likes 20078 views

2 Answers
Top Recommend | Recent
person
Ramesh , SubjectMatterExpert

Member since Apr 01 2014

HCF of 468 and 222

468 = (222 x 2) + 24
222 = (24 x 9) + 6
24 = (6 x 4) + 0

Therefore, HCF = 6

6 = 222 - (24 x 9)
= 222 - {(468 – 222 x 2) x 9 [where 468 = 222 x 2 + 24]
= 222 - {468 x 9 – 222 x 2 x 9}
= 222 - (468 x 9) + (222 x 18)
= 222 + (222 x 18) - (468 x 9)
= 222[1 + 18] – 468 x 9
= 222 x 19 – 468 x 9
= 468 x -9 + 222 x 19

Hence, HCF of 468 and 222 in the form of 468x + 222y is 468 x -9 + 222 x 19.

HOPE THIS WILL HELP YOU.