Question

plzz explan me properly I have not understand​

Answer 1

Step-by-step explanation:

Assume height of school is h .Observe small triangle

tan 45 =BC/CD=1 or CD=BC=h

Now in big triangle

tan 60 = AC/CD=√3

or AC=CD.√3=√3h

But CB is school and above it BA is flag so

AB=AC-BC=(√3-1)h=6

so

$h = \frac{6}{ \sqrt{3} - 1} \times \frac{ \sqrt{3} + 1 }{ \sqrt{3 + 1} } = 3( \sqrt{3} + 1)$