Question

plzz factorise this equation

Answer 1

HOLA!!

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HERE I'M TO EXPLAIN YOU :)


[Simple method ]
Step 1 --> Multiply the coefficient of x^2 with constant term

3 (2) =6

Step 2 ---> Now we find factors which can satisfy the following conditions

● The product of factors should give us the product of the coefficient of x^2 with constant term i .e, 6

● The sum of the factors should give us the the coefficient of x i.e, (-6)

So the factors can be either 6 , 1 or 3,2

But see 6 (1) = 6 but 6 +1 = 7 (not satisfied )

3 (2) = 6 but 3+2 = 5 (not statisfied )

Even you can check by applying negative sign to the digits , you will not get that.

So our conclusion is

This cannot be factorised.

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HOPE IT HELPS :)

Answer 2

(√3x)^2-2×√3x×√3+3-3+2=0
(√3x-√3)^2 - ( 1)^2=0
(√3x-√3+1)(√3x-√3-1)=0
x=-1+√3/√3 or x=1+√3/√3




hope it helps you if you are satisfied then plzz mark me as brainliest