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Let the two sides be x and x + 3
Area = 54 cm^2
1/2 (x)(x+3) = 54
x² + 3x = 108
x² + 3x - 108 = 0
(x+12)(x-9) = 0
x = 9
Sides are 9 cm and 12 cm
Hypotenuse = \sqrt{9^2 + 12^2}
= \sqrt{81 + 144}
= \sqrt{225}
= 15 cm
Perimeter of triangle = 9 + 12 + 15 = 36 cm
Area = 54 cm^2
1/2 (x)(x+3) = 54
x² + 3x = 108
x² + 3x - 108 = 0
(x+12)(x-9) = 0
x = 9
Sides are 9 cm and 12 cm
Hypotenuse = \sqrt{9^2 + 12^2}
= \sqrt{81 + 144}
= \sqrt{225}
= 15 cm
Perimeter of triangle = 9 + 12 + 15 = 36 cm
Answered by
1
Answer is 972
phle 54 ka square karo
phir 3 sse divide kar do
phle 54 ka square karo
phir 3 sse divide kar do
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