Question

plzz fast..............​

Answer 1

It will have no solution i think it may be wrong but experts se confirm kar lo sis

Hope this helps you

Answer 2

$\huge \rm\red {An} \green{sw} \pink{er} \checkmark$

$\star\mapsto \: \: \bf{x - 4y - 6 = 0}$

In the above equation ↑ ,

$a_{1}=1 , b_{1} = -4 , c_{1} = -6$

&

$\star \mapsto \bf{ \: \: 3x - 12y - 18 = 0}$

In the above equation ↑ ,

$a_{2} = 3 , b_{2} = -12 , c_{3} = -18$

Now , here ,

$\pink{ \colon\longrightarrow} \: \frac{a _{1} }{ a_{2} } = \frac{1}{3} \\ \\ \pink{ \colon \longrightarrow} \: \frac{ b_{1} }{ b_{2} } = \frac{ - 4}{ - 12} = \frac{1}{3} \\ \\ \pink{ \colon \longrightarrow} \: \frac{ c_{1} }{ c_{2} } = \frac{ - 6}{ - 18} = \frac{1}{3}$

$\sf{since} \\ \\ \green\hookrightarrow \: \frac{ a_{1} }{ a_{2}} = \frac{ b_{1} }{ b_{2}} = \frac{ c_{1} }{ c_{2} }$

So,

These pair of lines have Infinite Solution !

Option C is correct