Math, asked by Anonymous, 1 year ago

Plzz fast............

Attachments:

Answers

Answered by Bharadwaj981
1
logx=Lamda(y-z)
logy=lamda(z-x)
logz=lamda(x-y)

1)logx+logy+logz=Lamda(y-z+z-x+x-y)
log(xyz)=0
xyz=e^0 =>xyz=1

Sorry for second and third i dont get it
Similar questions