plzz find the value of x
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1
hey mate
refer to attachment
refer to attachment
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arsh77777:
thnku
Answered by
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Hi there!
Here's the answer:
•°•°•°•°<><><<><>><><>•°•°•°•°•
Given,

=>
=>
=>
=>![(1-x) = cos[cos^{-1}(1-2x^{2})] (1-x) = cos[cos^{-1}(1-2x^{2})]](https://tex.z-dn.net/?f=%281-x%29+%3D+cos%5Bcos%5E%7B-1%7D%281-2x%5E%7B2%7D%29%5D)
=>
=>
=>
=> x = 0 or x =
• Check if x=
satisfies the equation
LHS =
=
=
=
=
=/= RHS
• Check if x= 0 satisfies the equation
LHS =
=
=
=
=
= RHS
•°• x = 0 is the required solution
•°•°•°•°<><><<><>><><>•°•°•°•°•
Here's the answer:
•°•°•°•°<><><<><>><><>•°•°•°•°•
Given,
=>
=>
=>
=>
=>
=>
=>
=> x = 0 or x =
• Check if x=
LHS =
=
=
=
=
=/= RHS
• Check if x= 0 satisfies the equation
LHS =
=
=
=
=
= RHS
•°• x = 0 is the required solution
•°•°•°•°<><><<><>><><>•°•°•°•°•
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