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HERE IS YOUR ANSWER :-
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Let p be the smaller force then it is given that
p + q = 18. ------------(1)
R = √P^2 + q^2 + 2pqcos¢. = 12 ------(2)
q sin¢/p+cos. ¢ = tan¢ = tan90°
p+ qcos¢ = 0 ---------(3)
substituting the value of p
q (1- cos ¢ ) =18 ----------(4)
and subtracting square of equation (2) from (1)
2 pq [1-cos¢] = 18^2 - 12^2 = 180 -----------(5)
Dividing equation (5) by (4)
2p = 10
p= 5 , so q = 13
so the magnitude of forces are (5 and 13)
hence , correct answer is (c)
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I HOPE IT MAY HELPFUL FOR YOU ✌✌ ✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌
_____________________________
______________________________
HERE IS YOUR ANSWER :-
_______________________
_______________________
Let p be the smaller force then it is given that
p + q = 18. ------------(1)
R = √P^2 + q^2 + 2pqcos¢. = 12 ------(2)
q sin¢/p+cos. ¢ = tan¢ = tan90°
p+ qcos¢ = 0 ---------(3)
substituting the value of p
q (1- cos ¢ ) =18 ----------(4)
and subtracting square of equation (2) from (1)
2 pq [1-cos¢] = 18^2 - 12^2 = 180 -----------(5)
Dividing equation (5) by (4)
2p = 10
p= 5 , so q = 13
so the magnitude of forces are (5 and 13)
hence , correct answer is (c)
________________________________
I HOPE IT MAY HELPFUL FOR YOU ✌✌ ✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌
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______________________________
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