Question

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Answer 1

Given :

• Length of rectangular floor = 12m
• Breadth of rectangular floor = 8m
• Side of square tile = 50cm
• Cost of 1 square tile = ₹40

To find :

Total cost of tile to be laid on floor

Formula used :

• Area of rectangle = length × breadth
• Area of square = (side)²

Solution :

Firstly we will find area of floor ,

Area of floor = 12m × 8m

Area of floor = 96m²

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Area of one tile = 50cm × 50cm

Area of one tile = 2500cm²

Area of one tile = 2500/10000 m²

Area of one tile = 0.25 m²

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Now for covering floor with tile,

Area of floor = Number of tile used × Area of one tile

96m² = Number of tile used × 0.25m²

Number of tile used = 96m² ÷ 0.25m²

Number of tile used = 384

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Total cost = Cost of one tile × Number of tile used

Total cost = ₹40 × 384

Total cost = ₹ 15360

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ANSWER : ₹15360

Answer 2

Step-by-step explanation:

$\frak Given = \begin{cases} &\sf{Length\ of\ rectangular\ floor\ =\ 12m.} \\ &\sf{Breadth\ of\ rectangular\ floor\ =\ 8m.} \\ &\sf{Side\ of\ square\ tile\ =\ 50cm.} \\ &\sf{Cost\ of\ one\ square\ tile\ =\ Rs.\ 40.} \end{cases}$

To find:- We have to find the total cost of tile to be laid on the floor ?

_________________

$\frak{\underline{\underline{\dag As\ we\ know\ that:-}}}$

$\sf\pink{\underline{Area\ of_{(rectangle)}\ =\ length\ ×\ breadth}}$

$\sf\pink{\underline{Area\ of_{(square)}\ =\ (side)²}}$

$\frak{\underline{\underline{\dag Now,\ we\ find\ the\ area\ of\ floor:-}}}$

$\sf : \implies {Area\ of\ floor\ =\ 12m\ ×\ 8m} \\ \\ \sf : \implies {\purple{\underline{Area\ of_{(floor)}\ =\ 96m².}}}\bigstar$

________________

$\frak{\underline{\underline{\dag Now,\ finding\ area\ of\ one\ tile:-}}}$

$\sf : \implies {Area\ of\ one\ tile\ =\ 50cm\ ×\ 50cm} \\ \\ \sf : \implies {Area\ of\ one\ tile\ =\ 2500cm²} \\ \\ \sf : \implies {Area\ of\ one\ tile\ =\ \dfrac{2500}{10000}\ m²} \\ \\ \sf : \implies {\purple{\underline{Area\ of_{(one\ tile)}\ =\ 0.25m².}}}\bigstar$

________________

$\frak{\underline{\underline{\dag Now,\ finding\ the\ number\ of\ tile\ used:-}}}$

$\sf : \implies {Area\ of\ floor\ =\ Number\ of\ tile\ used\ ×\ Area\ of\ one\ tile} \\ \\ \sf : \implies {96m²\ =\ Number\ of\ tile\ used\ ×\ 0.25m²} \\ \\ \sf : \implies {Number\ of\ tile\ used\ =\ \dfrac{96}{0.25}} \\ \\ \sf : \implies {\purple{\underline{Number\ of_{(tiles\ used)}\ =\ 384.}}}\bigstar$

________________

$\frak{\underline{\underline{\dag Now,\ we\ will\ find\ the\ total\ cost:-}}}$

$\sf : \implies {Total\ cost\ =\ Cost\ of\ one\ tile\ ×\ Number\ of\ tiles\ used} \\ \\ \sf : \implies {Total\ cost\ =\ Rs.\ 40\ ×\ 384} \\ \\ \sf : \implies {\purple{\underline{Total_{(cost)}\ =\ Rs.\ 15360.}}}\bigstar$

Hence:-

$\sf \therefore {\underline{Total\ cost\ =\ Rs.\ 15360.}}$