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Let AB be the house of 11m
CD be the lamp post
|_ACX= 30°
|_ADB=60°
in ∆ABD,
tan60°=AB/BD=√3
=11/BD=√3
=11/√3=BD
=11√3/3=BD
in ∆ACX,
tan30°=AX/CX=1/√3
=AX/11√3/3=1/√3. (as CX=BD)
=AX=1/√3 X 11√3/3.
=AX=11/3 cm
CD= AB - AX
= 11- 11/3
=33/3 - 11/3
=22/3
= 7.34cm
hope you understand the answer.
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