Question

plzz give the answer​

Answer 1

Step-by-step explanation:

here is ur answer dude.....

pls mark me as brainliest......

Answer 2

$\bold\green{\underline{Given:}}$

$= > {x}^{2} + \frac{1}{ {x}^{2} } = 18$

$\bold\orange{\underline{Find:X-\frac{1}{X}=?}}$

• Here , using identity

=>(a-b)²=a²-2ab+b²

$= > (x - \frac{1}{x} ) {}^{2} \\ \\ = > {x}^{2} - 2 \times x \times \frac{1}{x} + \frac{1}{ {x}^{2} } \\ \\ = > ({x}^{2} + \frac{1}{ {x}^{2} } ) - 2$

• Now putting value of x²+1/x²
• 18-2
• 16

$= > (x - \frac{1}{x} ) {}^{2} = 16 \\ \\ = > x - \frac{1}{x} = \sqrt{16} \\ \\ = > x - \frac{1}{x} = 4$

Hence,

$\bold\green{\underline{The\: value\:of\:X-\frac{1}{X}=4}}$