Question

Plzz give the answer of the question !! Urgentttt

Answer 1

$\bold{\underline{Hey\: Mate\: ! }}$

According to the question

$\huge{\bold{[\frac{5}{8}]^{-7} \: \times \: [\frac{8}{5}]^{-5}}}$

In the given we reverse any one side exponential system to get the same in both so that m and n become m and m

No reversing the exponential powers symbol of negative and positive change vice - versa like :

$\huge{\boxed{x\: =\: \frac{1}{x^{-1}}}}$

$[\frac{5}{8}]^{-7} \: \times \: [\frac{5}{8}]^{5}$

We have a exponential rule :

$m^{a} \times m^{b} = m^{a+b}$

$[\frac{5}{8}]^{-7+5}$

$[\frac{5}{8}]^{-2}$

$[\frac{8}{5}]^{2}$

$\frac{64}{25}$

$\bold{\underline{Answer}}$

$\boxed{\frac{64}{25}}$

Thanks for question

$<marquee = down > Thanks$