Question

plzz give the answer quickly​

Answer 1

Answer:

3) 1/√x is the answer

Explanation:

x=[C]^2/[A]^2[B]

K of the given eqn. =[A][B]^(1/2) /[C]

=1/√x

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Answer 2

Question:

• For reaction, 2A + B <-----> 2C, k = x. Then, the equilibrium constant for , C <----> A + 1/2B will be

1. x
2. x/2
3. 1/√x
4. √x

Answer:

$\large\bold\red{(3)\frac{1}{\sqrt{x}}}$

Explanation:

Given,

A chemical reaction,

• 2A + B <------> 2C

Equilibrium constant, k = x

Therefore,

We get,

$= > \bold{\frac{ {C}^{2} }{ {A}^{2}B } = x}$

Now,

For the reaction,

• C <-------> A + 1/2B

Let, the equilibrium constant be m

Therefore,

We get,

$= > m = \frac{A \sqrt{B} }{C} \\ \\ = > m = \sqrt{ \frac{ {A}^{2} B}{ {C}^{2} } } \\ \\ = > m = \frac{1}{ \sqrt{ \frac{ {C}^{2} }{ {A}^{2}B } } }$

Now,

Substituting the values,

We get,

$= > \large \bold{ m = \frac{1}{ \sqrt{x} } }$

Hence,

(3) 1/√x is the correct answer.