Question

plzz guys ans this question plzz

Answer 1

here pq parrallel bc therefore
angle p=b and q=c (alternate interior angle)
so by AA similarity∆APQ ~∆ABC
now we know that ratio of area of two similar triangles is equal to the square of its corrosponding side therefore
ar(∆APQ)/ar(∆ABC)=3^2/7^2
9/49
now from above equation we can let the area of ∆APQ as 9x thus area of ∆ABC will be 49x
now ar of quad pQCB=area of ∆ABC- area of ∆ APQ
160=49x-9x
40x=160and x=40
therefore putting value of x in eq of area of ∆ABC give us as 49x=49×40=1960 square unit.
hope u find it helpful if yes then plz mark it as brainliest.;):):-)

Answer 2

step by step solution