Question

plzz guys answer this

Answer 1

your answer is here ✌✌✌✌

Answer 2

Hey frnd here is ur ans.....

Given, msin0 + ncos0 = p

On squaring both side .....

m^2sin^2 0 + n^2cos^2 0 + 2 mn sin0cos0=p^2

similarly...

mcos0 - nsin0 = q

m^2cos^20 + n^2cos^2 0 -2 mn sin0cos0=p^2

On adding both the equation ....

m^2(sin^2 0+cos^2 0) + n^2(sin^2 0 + cos^2 0)=p^2+q^2

m^2 + n^2 = p^2 + q^2 .....hence proved ;)


Hope it helps you ✌✌


Thankyou ☺☺


Arya ❤