Question

plzz guys solve this sum ​

Answer 1

Step-by-step explanation:

Here,

AB = cliff = 100

ABCD is a rectangle . So AB = CD and BC = AD

All angles are right angles

In triagle ABC ,

tan60 = p/b

$\sqrt{3} = 100 \div x$

$x = 100 \div \sqrt{3}$

$x = 100 \sqrt{3} \div 3$

In right angle triangle ADE

tan30 = p/b

$1 \div \sqrt{3} = y \div (100 \sqrt{3} \div 3)$

y = 33.33 m

Therefore , height of tower = 100 + 33.33 =133.33 m.

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