plzz help in this question
Answers
Answer:
Bro Subject English
And Question Maths
Not Fair
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✤ Required Answer:
✒ GiveN:
- Point A is at (10,-2)
- Point B is at (1,-11)
- Point P is at (3,y)
- And, PA = PB
✒ To FinD:
- Value of y.........?
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✤ How to solve?
As per the question, The point P is at equidistant from point A and B. Or we can say that the distance between PA and PB are equal. So, here we can use the distance formula which says that,
- The distance between two points A(x1, y1) and B(x2,y2) is given by,
⚘ Or distance between any points is the square root of squared difference of abscissae and squared difference of ordinates.
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✤ Solution:
We have,
- A at (10,-2)
- B at (1,-11)
- P at (3,y)
- PA = PB
By using distance formula,
➝ PA = PB
➝ √(10 - 3)² + (-2-(y))² = √(3-1)² + (y+11)²
Squaring both sides,
➝ 7² + (2+y)² = 2² + (y+11)²
➝ 49 - 4 = (y+11)² - (2+y)²
➝ 45 = y²+ 22y+ 121 - (4+ y²+ 4y)
➝ 45 = y²+ 22y+ 121 - 4- y²- 4y
➝ 45 = 18y + 117
➝ -72 = 18y
Flipping it,
➝ 18y = -72
➝ y = -72/18 = -4
☔ So, The correct answer is:
- y = -4 (Option B)
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