plzz help me ...........
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let usual speed of train = x
distance travelled = 300km
ATQ
300/x - 300/x+5 = 2
300(x+5-x) /x(x+5)=2
1500 = 2(x square +5x)
1500= 2x square +10x
2x square + 10x - 1500
now you plz solve your self by middle term split
distance travelled = 300km
ATQ
300/x - 300/x+5 = 2
300(x+5-x) /x(x+5)=2
1500 = 2(x square +5x)
1500= 2x square +10x
2x square + 10x - 1500
now you plz solve your self by middle term split
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