Question

plzz help me . answer with step by step explanation​

Answer 1

I hope this will helps u......

Answer 2

Hey Pretty Stranger!

Since,

|a sin x + b cos x| ≤ √a² + b² ∀x ∈ R

$\longrightarrow \sf \: |c| \leqslant \sqrt{ {a}^{2} + {b}^{2} }$

But

$\sf \: |c| > \sqrt{ {a}^{2} + {b}^{2} }$

$\therefore \sf \: a \sin \: x \: = \: b \cos x = c$

It doesn't hold for any x ∈ R

So, it hasn't any solution.

$\therefore$ Option 4) is the required answer.