Question

plzz help me
find the equation of straight line which passes through the point of intersection of the straight line 3x+4y=7 and 5x-2y=3 and perpendicular to the line 2x+3y=5​

Answer 1

Answer:

u can understand it with below example..

Step-by-step explanation:

question.

Find the equation of straight line which passes through the intersection point of 2x + 3y = 1, 3x + 4y = 6 and perpendicular to the line 5x – 2y = 7.

answer.

Let P (α, β) be the point of intersection of 2x + 3y = 1, 3x + 4y = 6

So,  2α + 3β – 1 = 0 ..... (1)

  and 3α + 4β – 6 = 0 ........ (2)

Solving (1) and (2) we get

Equation of the line perpendicular to 5x – 2y = 7

and Passing through P

is 2(x – 14) + 5(y + 9) = 0 

=> 2x – 28 + 5y + 45 = 0

  => 2x + 5y + 17 = 0