Math, asked by shivam996, 1 year ago

plzz help me for solving this question of linear equations in one varible

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Answered by ashk02
0
Actual length of wire= 4x
Length of one side = x
Area with length of one side x = x^2

Length of wire when 4cm is cut = 4x-4
Length of one side of square = x-1
Area with length x-1 = (x-1)^2=x^2+1-2x

Difference in areas = 25
x^2-x^2-1+2x= 25
2x-1= 25
2x= 26
x= 13 cm

Therefore actual length of wire = 4x= 52cm
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