Question

plzz help me guys.....

Answer 1

1st part
cosec^2@ - cot^2@ / 2( sin^2@+ cos^2@)

=1/2
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2nd part

2cos^2(60°) tan^2(28°)× cot^2(28°) / 3(sec^2(43°)- tan^2(43°)

2×(1/2)^2 /3
=(1/2) /3

= 1/6
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3rd part

cot 40°/tan40°

=1


add all of them
$\frac{1}{2} + \frac{1}{6} + 1 \\ = \frac{3 + 1 + 6}{6} \\ = \frac{10}{6} \\ = \frac{5}{3}$
Ans is 5/3