Question

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Answer 1

Answer:

In △ADC, ∠ADC=90

o

∴AC

2

=AD

2

+CD

2

(By Pythagoras theorem) .......... (1)

In △DBA, ∠ADB=90

o

∴AB

2

=AD

2

+BD

2

(By Pythagoras theorem) .......... (2)

Subtracting (1) from (2), we get

AB

2

−AC

2

=AD

2

+BD

2

−AD

2

−CD

2

∴AB

2

−AC

2

=BD

2

−CD

2

∴AB

2

+CD

2

=BD

2

+AC

2