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Answer:
In △ADC, ∠ADC=90
o
∴AC
2
=AD
2
+CD
2
(By Pythagoras theorem) .......... (1)
In △DBA, ∠ADB=90
o
∴AB
2
=AD
2
+BD
2
(By Pythagoras theorem) .......... (2)
Subtracting (1) from (2), we get
AB
2
−AC
2
=AD
2
+BD
2
−AD
2
−CD
2
∴AB
2
−AC
2
=BD
2
−CD
2
∴AB
2
+CD
2
=BD
2
+AC
2
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