Question

Plzz help me in doing this........

Answer 1

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a)36x^2-1/169

=(6x)^2-(1/13)^2 【using a^2-b^2=(a+b)(a-b)】

=(6x+1/13)(6x-1/13)
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b)16x^2-(5y+z)^2

=(4x)^2-(5y+z)^2 【using a^2-b^2=(a+b)(a-b)】

={4x+(5y+z)}{4x-(5y+z)}

=(4x+5y+z)(4x-5y+z)
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