Question

Plzz help me in solving this

Answer 1

Let < AB be minor arc
:.chord AB = radius OA = radius OB
:. All the three sides are equal
:. AOB is a equilateral
:. < AOB = 60*
Now
< AOB +< BOA = 360 * ( cmplt angle)
60* + < BOA = 360-60= 300
< BOA= 300

D is a point int the minor arc
Now
< BOA = 2 = < BDA = 1/2 = 150
Thus the angle subtended by major arc BA at any point B in the minor arc is 150

Let E be a point in the major arc AEB

= < AOB = 2 :. < AEB = 1/2 < AOB = 1/2 ✖️60 =30