Math, asked by jham, 10 months ago

plzz help me in this question

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Answered by sakshimahajan429
0

Answer:

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Answered by supriths4804
1

Answer:

Mode = 12.85

Step-by-step explanation:

Since 16 is the highest frequency,

10-20 is the modal class.

Lower limit (l) =10

Frequency of modal class (f1) =16

Frequency of preceding class (f0)=12

Frequency of succeeding class(f2) =6

Class size (h) = 10

Mode = l+(f1-f0)/(2f1-f0-f2) ×h

=10+(16-12)/(2×16-12-6)×10

=10+(4/(32-18))×10

=10+(4/14)×10

=10+(2/7)×10

=10+(20/7)

=10+2.85

=12.85

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