Question

plzz help me... maths..... ii) question

Answer 1

yess
here it is

in ∆ADB and ∆ADC,
seg AB =seg AC. .......given
<ADB =< ADC. .......each 90°
seg BD = seg CD. because D is midpoint

therefore, ∆ADB =∆ADC. ......hypotenuse test



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