Question

plzz help me out urgently.

Answer 1

let x be the first consecutive positive integer, then
x, x+1, x+2 are the three positive consecutive integers and p = x+1
now we are given,
3*(x+2)^2 = x^2 + (x+1)^2 + 67
calculate squares
3*(x^2+4x+4) = x^2 +(x^2+2x+1) +67
multiply and combine like terms
3x^2+12x+12 = 2x^2+2x+68
subtract 2x^2 from both sides of =
x^2 +12x +12 = 2x +68
subtract 2x +68 from both sides of =


x^2 +10x -56 = 0
fact this polynomial
(x-4)*(x+14) = 0
x is 4 or -14