Math, asked by SimranAnand, 1 year ago

Plzz help me.... Plzz give a short explanation too...

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Answered by manuparjapati64Mannu
1
I hope this will helpful for you
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Answered by sivarajarajeswari
2
The road roller is cylinder
Radius=84/2=42cm
Length=1m=100cm
Lateral surface area=2 \pi rh
                                   =2*22/7*42*100
                                    =26400cm^2
Area levelled by roller in one revolution=26400cm^2
Area levelled by 750 revolutions=750*26400cm^2
                                                         =750*26400
                                                           ----------------m^2
                                                           100*100
                                                           =15*132m^2
                                                           =1980m^2
therefore,area of road levelled by roller =1980m^2

sivarajarajeswari: hope it helps u
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