plzz.... help me to do this prblm
Attachments:
Answers
Answered by
0
Step-by-step explanation:
i) 2x^2+x-4=0
=> 2x^2+(4-2)x-4=0
=> 2x^2+4x-2x-4=0
=>2x(x+2)-2(x+2)=0
=>(x+2)(2x-2)=0
either, x+2=0, x= -2
or, 2x-2=0 , 2x=2, x=2/2, x=1
iii)5x^2-7x-6=0
=>5x^2-(10-3)x-6=0
=>5x^2-10x+3x-6=0
=>5x(x-2)+3(x-2)=0
=>(x-2)(5x+3)=0
either, x-2=0, x=2
or, 5x+3=0, 5x= -3, x= -3/5
iv) x^2+5= -6x
=>x^2+6x+5=0
=>x^2+(5+1)x+5=0
=>x^2+5x+x+5=0
=>x(x+5)+1(x+5)=0
=>(x+5)(x+1)=0
either, x+5=0, x= -5
or, x+1=0, x= -1
Similar questions
Biology,
2 months ago
Computer Science,
2 months ago
Economy,
2 months ago
Social Sciences,
5 months ago
Math,
11 months ago
Chemistry,
11 months ago
Chemistry,
11 months ago