Question

plzz help me to find out this answer

Answer 1

Given : AB = AC

To Prove : BE = EC

In given figure you can observe that

AD = AF (tangents from same exterior point are always equal)

BD = BE (tangents from same exterior point are always equal)  ----- ( i )

CE = CF (tangents from same exterior point are always equal)   ---- ( ii )

Now

AB = AC (given)

Lets split both the lines

AD + BD = AF + CF

BD = CF ( ∵ AD = AF proved above cancelled from each other)

from eq ( i ) and (ii) putting values of BD and CF, we get

∴ BE = CE   Hence proved

Answer 2

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