Question

plzz help me today is my exam....​

Answer 1

hope it will help you

Answer 2

SAKSHI BIDWE (PATIL)

UR ANS IS HERE

Consider An area if cross section of pipe as shown in fig

radius of circular end of pipe = 0.1m

area of cross section = pie r2

= 0.01 pie m^2

speed of water = 3 km / h = 3000/ 60= 50 m/min

volume of water that flows in 1min from pipe = 50* 0.01 pie = 0.5 pie m^3

volume of water flows in t min = t*0.5pie m^3

radius of cy= 5m

depth = 2m

let the tank b fileld in t minutes

volume of tank in t min is equal to volume of water flowed in t min from pipe

volume of water that flows in t min from pipe = volume if water in tank

= t* 0.5 p8e = pie * r^2 * h

=t* 0.5 pie = 25*2

t = 100

therefore the cylindrical tank will be filed in 100 min

hope it help

with regards sakshi

be brainly ︽⊙＿⊙︽☺