plzz help me with this question.. as early as possible
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given
Ax. = BY
AX||BY
angle XAP =BYP
because we have given ax = by
A B alternate angle so that angle is XAP = BYP
so that same theorem is applied on it
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Step-by-step explanation:
- in ∆ APX and ∆ BPY
- AX=BY (GIVEN)
- angle (APX)= angle(YPB) ( VERTICAL OPPOSITE ANGLE)
- angle(XAP)= ANGLE(BYP) (ALTERNAT ANGLES)
- THEREFORE ∆apx congurent ∆BPY (ASA)
- THEREFORE ANGLE APX = ANGLE BPY (C.PC.T)
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