plzz help me with this
y= loge sinx
find dy/dsinx and dy/dx
Answers
Answered by
1
Explanation:
dy/dx=dlogesinx/dsinx ×dsinx/dx
dy/dx=1/sinx×cosx
dy/dx=cos/sinx
dy/dx=cotx....
Answered by
1
Hope it helps u................
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nikki170603:
Thanku very very much
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