plzz...help......!!....plzzzz...#seriously need solution..
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cuteprincess49:
can i ask u why all u r just staring the question.. and not answering..?
r u Pakistani
me..?
if u asking to me then no..
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As i^ ( 4n) = 1
So i^ (0!) + i^ ( 1!) + i^ (2!) + i( 3!) + i^(4!) +.......i^(100!)
As i^ (4!) , i^(5!)........i^(100!) all are multiples of 4
therefore there value is 1
So value is (100 -4 +1) = 97
Now i^(0!) + i^(1!) + i^( 2!) + i^ (3!) + 97
1 + i -1 - i +97
97
So i^ (0!) + i^ ( 1!) + i^ (2!) + i( 3!) + i^(4!) +.......i^(100!)
As i^ (4!) , i^(5!)........i^(100!) all are multiples of 4
therefore there value is 1
So value is (100 -4 +1) = 97
Now i^(0!) + i^(1!) + i^( 2!) + i^ (3!) + 97
1 + i -1 - i +97
97
hi dhruv ...i asked this que i need ur help this is mah new id . I had posted some PHY question plz if u r free then try them plz and help me:)
solve other...plz if u can:)
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